求sin^4π/8+cos^4π/8的值

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求sin^4π/8+cos^4π/8的值
求sin^4π/8+cos^4π/8的值

求sin^4π/8+cos^4π/8的值
=(sin²π/8+cos²π/8)²- 2sin²π/8cos²π/8
=1- (1/2)sin²π/4
=1-1/4=3/4

sin^4π/8+cos^4π/8+4sin^2π/8cos^2π/8-4sin^2π/8cos^2π/8
=(sin^2π/8+cos^2π/8)^2-(sinπ/4)²
=1-1/2
=1/2

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