当0当0当0|1-x^2|=|x^2-1|所以|1-x^2|=kx+k|(x+1)(x-1)|=k(x+1)|x-1|=kx-1=k和-k所以x1=1+kx2=1-k两个实根.
当0|1-x^2|=|x^2-1|所以|1-x^2|=kx+k|(x+1)(x-1)|=k(x+1)|x-1|=kx-1=k和-k所以x1=1+kx2=1-k两个实根.