α∈(3π\4,5π\4),sin(α+π\4)=-3\5,则cosα= sin2α=

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α∈(3π\4,5π\4),sin(α+π\4)=-3\5,则cosα= sin2α=
α∈(3π\4,5π\4),sin(α+π\4)=-3\5,则cosα= sin2α=

α∈(3π\4,5π\4),sin(α+π\4)=-3\5,则cosα= sin2α=
因为α∈(3π\4,5π\4),
所以π

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