x+y=8 y+z=12 x+z=10 x+y+z=

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x+y=8 y+z=12 x+z=10 x+y+z=
x+y=8 y+z=12 x+z=10 x+y+z=

x+y=8 y+z=12 x+z=10 x+y+z=
x+y+z=(x+y+y+z+x+z)/2=(8+12+10)/2=15

三次相加除以2
=15

x+y=8 ..................1
y+z=12 ...................2
x+z=10 ...................3
1+2+3 2(x+y+z)=30
x+y+z=15

15

x+y=8 y+z=12 x+z=10
2(x+y+z)=30,x+y+z=15

x+y=8 ....1
y+z=12....2
x+z=10 ...3
1+2+3,得2(x+y+z)=30,所以x+y+z=15

x+y+z=(x+x+y+y+z+z)/2=(8+12+10)/2=15

(x+y)+(y+z)+(x+z)=12+8+10=30
即2x+2y+2z=30
则x+y+z=15