作业帮lg5^2+2/3lg8+lg5*lg20+lg2^2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/13 04:32:19
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+2/3lg8+lg5*lg20+lg2^2
=lg5²+2lg2+lg5lg20+lg²2 后面的一个应该是lg²2
=2lg5+2lg2+(1-lg2)(1+lg2)+lg²2
=2(lg5+lg2)+1-lg²2 +lg²2
=2+1
=3
原式=lg5^2+2/3*lg2^3+lg5*lg(5*2^2)+lg2^2
=2lg5+2lg2+lg5*(lg5+2lg2)+2lg2
=2(lg5+lg2)+(lg5)^2+2lg5*lg2+2lg2
=2lg10+(lg5)^2+2lg5*lg2+2lg2
=2+(lg5)^2+2lg5*lg2+2lg2
=[(lg5)^2+2lg5*lg2+(lg...
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原式=lg5^2+2/3*lg2^3+lg5*lg(5*2^2)+lg2^2
=2lg5+2lg2+lg5*(lg5+2lg2)+2lg2
=2(lg5+lg2)+(lg5)^2+2lg5*lg2+2lg2
=2lg10+(lg5)^2+2lg5*lg2+2lg2
=2+(lg5)^2+2lg5*lg2+2lg2
=[(lg5)^2+2lg5*lg2+(lg2)^2]-(lg2)^2+2lg2+2
=(lg5+lg2)^2-(lg2)^2+2lg2+2
=(lg10)^2-(lg2)^2+2lg2+2
=1^2-(lg2)^2+2lg2+2
=-(lg2)^2+2lg2+1
=-(lg2-1)^2+2
收起
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
（lg5)平方+2/3lg8+lg5乘lg20+（lg2)平方
3lg2+2lg5+lg5乘以lg8怎样算
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
lg5^2+2/3lg8+lg5*lg20+(lg2)^2 lg5*lg20怎么办啊
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
对数lg2*lg5=?2lg（5）+2/3 lg8+lg5*lg20+lg2 =lg5^2+lg8^(2/3)+lg5*(lg4+lg5)+lg2 =lg100+lg5+2lg2*lg5+lg2 =2+(lg5+lg2) =2+1 =3 第二个等号lg5*(lg4+lg5)为什么=lg5+2lg2*lg5
lg5（2）+2/3lg8+lg5*lg2+（lg2）^2
计算：（lg2)2+3lg5+lg5(1+lg2)+lg8+log2（5）log5（4)
化简[(1-lg5)^2+lg2乘lg5]/lg8
lg25+2/3lg8+lg5*lg20+(lg2)^2
（lg2）^2+lg25+2/3lg8+lg5*lg20=?
lg25+2/3lg8+lg5*lg20+（lg2）^2=?
lg25+(2/3)lg8+lg5.lg20+(lg2)^2
lg25+(2/3)lg8+lg5.lg20+(lg2)^2=?