X-Y-Z=4 3Y-X-Z=8 7Z--X-Y=16 这三个方程联立求x y z请把解的步骤写下来,越详细越好,我想知道这究竟是怎么解的,

{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z= 三元一次方程组2x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=262x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=26 x+y-z=3 y+z-x=5 z+x-y=7 求x,y,z (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? fangchengzu:X+Z=Y 7Z=X+Y+Z X+Y+Z=14 (x+y-z)(x-y+z)= x-4y+z=-302x+y-z=18x--y-z=7 x+y/2=z+x/3=y+z/4 x+y+z=27 (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z x+2y=3x+2z=4y+z 求x:y:z 3x+2y+z=3 2x=4-3z=-8 x+y-2z=-4 2x+y+3z=7 解下列三元一次方程组:(1)x-z=4,x+y-z=-1,2y-z=1 (2)3x+4z=7,2x+3y+z=9,x-y+z=8 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 x,y,z不是0.3z=4y,z=3x求（x+y）：（x+z）. 24xy²z²(x+y-z)-32xyz(z-x-y)²+8xyz³(z-x-y) 为 -8xyz(z-x-y)(3yz+4z-4x-4y+z²)我的过程是这样的：解：原式=-24xy²z²(z-x-y)-32xyz(z-x-y)²+8xyz²(z-x-y)=-[24xy²z²(z-x-y)+32xyz(z-x-y)²+8 X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..