试比较2+|m|分之1+|m|与3+|m|分之2+|m|的大小

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试比较2+|m|分之1+|m|与3+|m|分之2+|m|的大小
试比较2+|m|分之1+|m|与3+|m|分之2+|m|的大小

试比较2+|m|分之1+|m|与3+|m|分之2+|m|的大小
令a=|m|
则a≥0
(1+a)/(2+a)-(2+a)/(3+a)
=[(1+a)(3+a)-(2+a)²]/(2+a)(3+a)
=(3+4a+a²-4-4a-a²)/(2+a)(3+a)
=-1/(2+a)(3+a)
a≥0,所以(2+a)(3+a)>0
所以-1/(2+a)(3+a)<0
所以(1+a)/(2+a)<(2+a)/(3+a)
即(1+|m|)/(2+|m|)<(2+|m|)/(3+|m|)

(1+|m|)/(2+|m|)=1-1/(2+|m|);
(2+|m|)/(3+|m|)=1-1/(3+|m|);
|m|>=0;
3+|m|>2+|m|;
估1/(2+|m|)>1/(3+|m|);(1+|m|)/(2+|m|)<(2+|m|)/(3+|m|)

A:(1+|m|)/(2+|m|);B:(2+|m|)/(3+|m|)
A-B=(1+|m|)/(2+|m|)-(2+|m|)/(3+|m|)
=((1+|m|)×(3+|m|)-(2+|m|)×(2+|m|))/(2+|m|)×(3+|m|)
=((m²+4|m|+3)-(m²+4|m|+4))/m²+5|m|+6

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A:(1+|m|)/(2+|m|);B:(2+|m|)/(3+|m|)
A-B=(1+|m|)/(2+|m|)-(2+|m|)/(3+|m|)
=((1+|m|)×(3+|m|)-(2+|m|)×(2+|m|))/(2+|m|)×(3+|m|)
=((m²+4|m|+3)-(m²+4|m|+4))/m²+5|m|+6
= -1/m²+5|m|+6
∵-1/m²+5|m|+6<0
∴A<B

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