函数f(x)=3x/x+1的值域为_______

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函数f(x)=3x/x+1的值域为_______
函数f(x)=3x/x+1的值域为_______

函数f(x)=3x/x+1的值域为_______
y=3x/(x+1)
=(3x+3-3)/(x+1)
=(3x+3)/(x+1)-3/(x+1)
=3-3/(x+1)
因为 1/(x+1)≠0
所以 值域 y≠3

x不等于-1,即x>-1,x<-1

f(x)=(3x+3-3)/(x+1)
=(3x+3)/(x+1)-3/(x+1)
=3-3/(x+1)
-3/(x+1)≠0
所以值域是(-∞,3)∪(3,+∞)

R

f(x)=3x/(x+1)=3(x+1-1)/(x+1)=3-3/(x+1)
由于-3/(X+1)不=0
故函数不=3
即值域是(-无穷,3)U(3,+无穷)

f(x)=3x+3-3/x+1
=3-3/x+1
值域是{yIy≠3}

[0,+无穷]

∵5/(6x+3)≠0∴f(x) ≠-3/2 值域(-∞,-3/2),(-3/2,+∞) y=(1-3x)/(2x+1) x=(1-y)/(2y+3) 原函数值域为y≠-3/

<=3