设y=e^cos^2*1/x,求dy

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设y=e^cos^2*1/x,求dy
设y=e^cos^2*1/x,求dy

设y=e^cos^2*1/x,求dy
lny=cos^2(1/x)
两边求导:
1/ydy/dx=2cos(1/x)[cos(1/x)]'
1/ydy/dx=2cos(1/x)[-sin(1/x)]*[-1/x^2]
1/ydy/dx=2cos(1/x)sin(1/x)/x^2
1/ydy/dx=sin(2/x)/x^2
dy=y[sin(2/x)]/x^2dx
dy=[e^cos^2(1/x)]*[sin(2/x)]/x^2dx