作业帮求间算 1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)=
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求间算 1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)=
求间算 1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)=
求间算 1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)=
1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)
=1/(x-5y)－1/(x-8y)＋1/(x-9y)－1/(x-6y)
=[(x-8y)-(x-5y)]/[(x-5y)(x-8y)]+[(x-6y)-(x-9y)]/[(x-9y)(x-6y)]
=(-3y)/[(x-5y)(x-8y)]+ 3y/[(x-9y)(x-6y)]
=3y*{ 1/[(x-9y)(x-6y)] - 1/[(x-5y)(x-8y)] }
=3y*[(x-5y)(x-8y) - (x-9y)x-6y)]/[(x-9y)(x-6y)(x-5y)(x-8y)]
=3y*[(x²-13xy+40y²)-(x²-15xy+54y²)]/[(x-9y)(x-6y)(x-5y)(x-8y)]
=3y*(2xy-14y²)/[(x-9y)(x-6y)(x-5y)(x-8y)]
=6y²(x-7y)/[(x-9y)(x-6y)(x-5y)(x-8y)]
2x-6y/x^2-9y^2 =2（x-3y）/（x-3y）（x+3y）=2/（x+3y）2x+6y+1=0 2x+6y=-1x+3y=-1/2那么2/（x+3y）=2÷（-1/2）=-4
1/x-5y-1/x+6y-1/x+8y+1/x-9y =(2/x-2/x)+(6y-5y+8y-9y) =0
(x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
求间算 1/(x-5y)－1/(x-6y)－1/(x-8y)＋1/(x-9y)=
(x+5y)(x-7y-1)
(x+y)(x-y)+4(y-1)
y''-5y'+6y=3x+1通解
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
计算：5x-2y-6+ (1/x) + (1/y)
5x+y=6 2x-y=1
y＝5；x＝14；y＝（（x＝3*y,x＋6）,x－1）； printf（''x＝%d,y＝%d'y＝5；x＝14；y＝（（x＝3*y,x＋6）,x－1）；printf（''x＝%d,y＝%d'',x,y）；
把(x-y)看作一个整体,化简:(1)5(x-y)+2(x-y)-4(x-y);(2)3(x-y²-4(x-y)+7（x-y)-6(x-y)
｛x-y=4 ｛5x-y=110 4x-y=－1 9y-x=110
y-x/7-x+y/6=1/2 5(x+y)-2(y-x)=1怎么解答
x+y/2+x-y/3=5/6;x=y/6-x-y/3=1/2
已知:2x-y/x+y=1/5,求2x+5y/6x-2y的值
解方程组6(x-y)-7(x+y)=21 2(x-y)-5(x+y)=-1
是两元一次方程组｛6(x-y)-7(x+y)=212(x-y)-5(x+y)=-1
初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x