作业帮log(2)2/3+log(2)6+log(4)8=
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log(2)2/3+log(2)6+log(4)8=
log(2)2/3+log(2)6+log(4)8=
log(2)2/3+log(2)6+log(4)8=
log(2)2/3+log(2)6+log(4)8
= log(2)2/3+log(2)6+log(2²)8
= log(2)2/3+log(2)6+1/2log(2)8
=log(2)2/3+log(2)6+log(2)(2√2)
=log(2)(2/3×6×2√2)
=log(2)(8√2)
=log(2)(2^7/2)
=7/2
这是我在静心思考后得出的结论,
如果不能请追问,我会尽全力帮您解决的~
如果您有所不满愿意,请谅解~
log(2)2/3+log(2)6+log(4)8
=log(2) [(2/3)*6] + (1/2)*log(2) 8
=log(2) 4 + (1/2)*3
=2+ 3/2
=7/2
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log(2)9×log(3)4
4^[log(2)3+log(4)8]
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