一道分式方程~急1/x-2 = x-1/2-x - 3

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一道分式方程~急1/x-2 = x-1/2-x - 3
一道分式方程~急
1/x-2 = x-1/2-x - 3

一道分式方程~急1/x-2 = x-1/2-x - 3
你确定题目没错?
1/x-2 = x-1/2-x - 3 右边的两个x消掉了呀
1/x = -1/2-1=-3/2
x=-2/3
是不是 1/(x-2)=(x-1)/(2-x)-3
1/(x-2)+(x-1)/(x-2)=-3 两边乘以x-2
x=-3x+6
4x=6
x=3/2

1/x-2+(x-1)/x-2=3;x/x-2=3;x=3(x-2);x=3

1/(x-2) = (x-1)/(2-x) - 3
1/(x-2) = -(x-1)/(x-2) - 3
1/(x-2)+(x-1)/(x-2) =- 3
x/(x-2)=-3
x/(x-2)+3=0
(x+3x-6)/(x-2)=0
(4x-6)/(x-2)=0 (x-2≠0,否则分式无意义)
4x-6=0
x=3/2
经检验x=3/2是方程的根

1*(2-X)/X-2 =X-1-3*(2-X)
-1=4X-7
6=4X
X=3/2