代数式1/(x-1)+1/(x+1)+2x/(x²+1)+4x³/(x⁴+1)化简

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代数式1/(x-1)+1/(x+1)+2x/(x²+1)+4x³/(x⁴+1)化简
代数式1/(x-1)+1/(x+1)+2x/(x²+1)+4x³/(x⁴+1)
化简

代数式1/(x-1)+1/(x+1)+2x/(x²+1)+4x³/(x⁴+1)化简
1/(x-1)+1/(x+1)+2x/(x²+1)+4x³/(x⁴+1)
=(x+1+x-1)/(x-1)(x+1)+2x/(x²+1)+4x³/(x⁴+1)
=2x/(x²-1)+2x/(x²+1)+4x³/(x⁴+1)
=2x(x²+1+x²-1)/(x²-1)(x²+1)+4x³/(x⁴+1)
=4x³/(x⁴-1)+4x³/(x⁴+1)
=4x³(x⁴+1+x⁴-1)/(x⁴-1)(x⁴+1)
=4x³*2x⁴/[(x⁴)²-1]
=8x^7/(x^8-1)

按顺序加不就可以吗?=2x/(x^2-1)+2x/(x^2+1)+4x^3/(x^4+1)=4x^3/(x^4-1)+4x^3/(x^4+1)=8x^7/(x^8-1)