10(8y-x)=6(12y-x)=t(14y-x)t是多少

10(8y-x)=6(12y-x)=t(14y-x)t是多少 int x=12,y=8; printf(%d %d %d ,x,x&y,x|y); [T,Y]=ode45(@rigid,[0 1],[rand(15,1)]);plot(T,Y(:,1),'-',T,Y(:,2),'-.',T,Y(:,3),'.',T,Y(:,4),'-',T,Y(:,5),'-.',T,Y(:,6),'.',T,Y(:,7),'-',T,Y(:,8),'-.',T,Y(:,9),'.',T,Y(:,10),'-',T,Y(:,11),'-.',T,Y(:,12),'-.',T,Y(:,13),'.',T,Y(:,14),'-',T,Y(:,15),'.') 微分方程 矩阵 x'(t)=x(t)+y(t)+2t y'(t)=x(t)+y(t)-2t 设实数x,y满足方程:x^2+y^2-8x-6y+21=0 （1）求S=2x-y的最大值与最小值（2）求T=x^2+y^2-10x+2y+26的（2）求T=x^2+y^2-10x+2y+26的最大值与最小值. mathematica编程哪里错啦,急~~NDSolve[{y''[t] == -9.81, y[0] == 11, y'[0] == 0, x[t] = 1.5 t, WhenEvent[y[t] == 0, y'[t] -> -0.80 y'[t]], WhenEvent[y[t] == 0, x'[t] -> -0.80 x'[t]], WhenEvent[ Abs[y'[t]] < 1*10^(-6), {tf = Sqrt[x^2 + 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= 3x+2y=9,3x-y=-3 4x-3y=-4,X+y=-1 3x+2y=1,10x+6y=5 4x-3y=-4,3x+4y=2 2s-3t=8,7s-5t=-53x-2y=2,2x+2y=3 12y(x-y)^2-8(x-y)^3=? (x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5 {6/x+y+10/x-y=30 6/x+y-10/x-y=-1 y+y+x=10,x+y+x=8,y=?,x=? 已知|x|+x+y=10 |y|+x-y=12 求 x+y=? 已知|x|+x+y=10,|y|+x-y=12,求x+y的值 已知|x|+x+y=10,x+|y|-y=12,求x、y的值 x+y=10;8x+6y=66 X+Y-8X+10Y+41=O,求X/Y-Y/X的值 x,y 满足x(x-2)-y(y-6)=-10,求x,y的值