设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x=

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设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x=
设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /
设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x= 

设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x=

设f(x)=1/(1+e^(1/x)) 求 lim f(x) x->0 设f'(x)=2,求极限lim(x~0)[f(1-x)-f(1+x)]/x 设lim(x→0)[f(x)-3]/x^2=100,求lim(x→0)f(x) 设f(x)=当x0时为arccot-2/(x^2),求lim f(x) x->0-,lim f(x)x->0+,limf(x) x->0 设f(x)是多项式,且lim(x→∞)[f(x)-x^3]/x^2=2,且lim(x→0)f(x)/x=1,求f(x) 设f(x)有二阶导数,在x=0的某去心邻域内f(x)≠0,且lim f(x)/x=0,f'(0)=4,求lim (1+f(x)/x)^(1/x) 设f(x)连续,g(x) =∫(1,0)f(xt)dt,且lim x→0 f(x)/x =A,求 g'(x).如题 设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /设lim(x>0) f(x)/x=1,求lim(x->0) {[1+f(x)]^1/2 -1} /x= 极限问题: 设f(x)=arctan 1/(1-x) 求lim(x→1+)f(x) 和lim(x→1-)f(x) 设函数f(x)在点x=a可导,且f(a)不等于0,求lim(x趋向无穷)[(f(a+1/x)/f(a)]^x 设函数f x=e^2x-2x,lim f'(x)/e^x -1等于 ,x→0 已知f(x)=ln(1+x) 求lim(x→0) f(x)/x 设函数f(x)连续,lim((f(x)/x)-1/x-(sinx/x^2))=2,f(0)=? 设函数f(x)连续,lim((f(x)/x)-1/x-(sinx/x^2))=2,f(0)=? 设f(x)=e^(-x),则lim(x趋向于0) (f ' (1-2x)-f '(1)) / x f(x)={x x=1}求lim x趋向于1- f(x) lim x趋向于1+ f(x) lim趋向于1 f(x)f(x)={2x-1 x0} 求lim x趋向于0- f(x) lim x趋向于0+ f(x) lim趋向于0 f(x) 还是高数~崩溃崩溃~设f'(x)存在,且Lim(x->0) {f(1)-f(1-x)}/2x = -1,求f'(1). 利用函数极限求数列极限(例题)设函数f(x)=(tanx/x)^((1/(x^2))于是x趋于0 lim f(x) =x趋于0 lim(tan/x)^(1/(x^2))=e^lim x趋于0 ln (tanx/x)/(x^2)=e ^lim x趋于0 ((tan/x)-1)/(x^2)=e^lim x趋于0 (tanx-x)/(x^3)=e^1/3 lim x趋于0 (