计算:4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 14:04:05

计算:4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)
计算:4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)

计算:4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)
4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)
=㏒(10)(2^4)+㏒(10)(5^3)-㏒(10)(1/5)
=㏒(10)(2^4×5^3÷1/5)
=㏒(10)(10^4)
=4

原式=log(10)(2^4)+log(10)(5^3)-log(10)(1/5)
=log(10)(2^4*5^3*5)=4

4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)=4lg2+3lg5-lg(1/5)=4lg2+3lg5+lg5=4(lg2+lg5)=4

4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)
=Ig2^4+lg5^3-lg1/5
=lg(16*25*25)
=lg100^2
=lg10^4
=4

4㏒(10)(2)+3㏒(10)(5)-㏒(10)(1/5)
= ㏒(10)(2⁴) + ㏒(10)(5³) - ㏒(10)(1/5)
= ㏒(10) { 2⁴ × 5³ ÷ (1/5) }
= ㏒(10) { 2⁴ × 5³ × 5 }
= ㏒(10) { (10)⁴ }
= 4㏒(10) (10)
= 4