Find out F(1)=?If dy/dx =1/2x,and f(e)=0

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Find out F(1)=?If dy/dx =1/2x,and f(e)=0
Find out F(1)=?If dy/dx =1/2x,and f(e)=0

Find out F(1)=?If dy/dx =1/2x,and f(e)=0
dy/dx = 1/(2x)
y = (1/2)lnx + C
y(e) = 1/2+ C = 0
C= -1/2
y = (1/2)(lnx -1)
y(1) = -1/2

一楼的回答的是真确的

因为dy/dx =1/2x,所以求得F(X)=X^2+C,又 f(e)=0,所以C=-e^2,既F(X)=X^2-e^2.所以F(1)=1-e^2

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