log9 x+logx^2 3=1,求x.前面是底数,后面是真数

解方程 log9(x)-3logx^2(3)=1 log9 x+logx^2 3=1,求x.前面是底数,后面是真数 已知logx(a)=2 logx(b)=3 logx(c)=6 求logabc(x) logx+logx^2+log^3+.logx^10=110,求X的值帮帮忙哦 logx^2=3求x logX(1/8)=3/2,求x logx(x+1)+logx(x+2)=logx6+1 函数f(x)=1-logx（2）+logx^2（9）-logx^3（64）,那么是f(x) 求x,y值.6log9^x+3log27^y=8log3^x+2log9^y=2 log2(x)=-2/3 logx(3+2根号2) 求x.(1) log2(x)=-2/3 (2) logx(3+2根号2)=-2 。求x logx底8=-2求x log3(x-1)=log9(x+5) 求x log3(x-1)=log9(x-5) 求x logX=1.673006求X logX=1.794261求X logx(3+2倍根号2)= -2 求X logx(3-2√2)=2,求x logx（8）= 3/2,求x logx-1^(3x2-2x-1)=2,求x