已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?

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已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?
已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?

已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?
1/x-1/y=3
(y-x)/xy=3
y-x=3xy
x-y=-3xy
所以(2x+3xy-2y)/(x-2xy-y)
=[2(x-y)+3xy]/[(x-y)-2xy]
=-3xy/-5xy
=3/5

∵1/x-1/y=3
∴y-x=3xy
x-y=-3xy
2x+3xy-2y/x-2xy-y
=[2(x-y)+3xy]/[(x-y)-2xy]
=(-6xy+3xy)/(-3xy-2xy)
=-3xy/(-5xy)
=3/5

1/x-1/y=3
(y-x)/xy=3
y-x=3xy
x-y=-3xy
(2x+3xy-2y)/(x-2xy-y)
=[2(x-y)+3xy]/[(x-y)-2xy]
=(-6xy+3xy)/(-3xy-2xy)
=-3xy/(-5xy)
=3/5

y-x=3xy
代入
-3xy/-5xy=3/5

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