已知5a+7b=6,3a-4b=15,求11a-b的值

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已知5a+7b=6,3a-4b=15,求11a-b的值
已知5a+7b=6,3a-4b=15,求11a-b的值

已知5a+7b=6,3a-4b=15,求11a-b的值
(3a-4b)*2=6a-8b=30
(5a+7b)+(6a-8b)=11a-b=6+30=36

3a-4b=15 ,6a-8b=30 ......1
5a+7b=6 ......2 用1式加2式得:11a-b=36

5a+7b=6,3a-4b=15,即5a+7b=6,6a-8b=30,相加,即11a-b=36

5a+7b=6...1
3a-4b=15...2
1式加两倍2式得
11a-b=36.

5a+7b=6 ......1
3a-4b=15 ......2
1式+2式*2得:
11a-b=36

5a+7b=6 (1)
3a-4b=15 (2)
(2)两边乘3,得:
6a-8b=30 (3)
(3)+(1)
11a-b=36