已知x+1/6-x/10>2x+5,则|2x-1|-|1+2x|=
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已知x+1/6-x/10>2x+5,则|2x-1|-|1+2x|=
已知x+1/6-x/10>2x+5,则|2x-1|-|1+2x|=
已知x+1/6-x/10>2x+5,则|2x-1|-|1+2x|=
(x+1)/6-x/10>2x+5,
∴5x+5-3x>60x+150,
-145>58x,x
等于 -2 。
2
答案是2
解答如下:解不等式得x<-125/33
所以,|2x-1|=2(-x)+1=-2x+1
|1+2x|=-(1-2(-x))=-2x-1
所以,|2x-1|-|1+2x|=-2x+1-(-2x-1)=-2x+1+2x+1=2
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