若x^2+xy+y=14,y^2+xy+x=28,求x+y
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若x^2+xy+y=14,y^2+xy+x=28,求x+y
若x^2+xy+y=14,y^2+xy+x=28,求x+y
若x^2+xy+y=14,y^2+xy+x=28,求x+y
两式相加有
x²+y²+2xy+(x+y)=42
即 (x+y)²+(x+y)-42=0
即 (x+y+7)(x+y-6)=0
得到 x+y=-7 或 6
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