若(2x-3)^5=a0+a1x+a2x^2+a3x^3+.+a5x^5,则a1+2a2+3a3+4a4+5a5等于

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若(2x-3)^5=a0+a1x+a2x^2+a3x^3+.+a5x^5,则a1+2a2+3a3+4a4+5a5等于
若(2x-3)^5=a0+a1x+a2x^2+a3x^3+.+a5x^5,则a1+2a2+3a3+4a4+5a5等于

若(2x-3)^5=a0+a1x+a2x^2+a3x^3+.+a5x^5,则a1+2a2+3a3+4a4+5a5等于
令f(x)=(2x-3)^5=a0+a1x+a2x^2+a3x^3+.+a5x^5
则f'(x)=10(2x-3)^4=a1+2a2x+3a3x^2+4a4x^3+5a5x^4
代入x=1,得:f'(1)=10=a1+2a2+3a3+4a4+5a5.