sinx-1)/cosx怎么化成[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2
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sinx-1)/cosx怎么化成[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2
sinx-1)/cosx怎么化成[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2
sinx-1)/cosx怎么化成[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2
(sinx-1)/cosx
=(2sinx/2cosx/2 - sin^2 x/2 -cos^2 x/2)/(cos^2 x/2 -sin^2 x/2)
=-(cos^2 x/2 -sin^2 x/2)^2 //(cos^2 x/2 -sin^2 x/2)
=-(cosx/2 -sinx/2)/(cosx/2 +sinx/2)
=(sinx/2-cosx/2)/(cosx/2 +sinx/2)
简单
sinx-1)/cosx怎么化成[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2
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