求下列各式的值cos7π/12.(2)cos(-61π/12)利用公式Ca+β,Ca-β证明cos(a+π/2)=-sina (2)cos(-a+π/2)=sina

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求下列各式的值cos7π/12.(2)cos(-61π/12)利用公式Ca+β,Ca-β证明cos(a+π/2)=-sina (2)cos(-a+π/2)=sina
求下列各式的值cos7π/12.(2)cos(-61π/12)
利用公式Ca+β,Ca-β证明cos(a+π/2)=-sina (2)cos(-a+π/2)=sina

求下列各式的值cos7π/12.(2)cos(-61π/12)利用公式Ca+β,Ca-β证明cos(a+π/2)=-sina (2)cos(-a+π/2)=sina
(1)cos(7π/12)=cos(π/2+π/12)=-sin(π/12)=-(√6-√2)/4
(2)cos(-61π/12)=cos(61π/12)=cos(13π/12)=cos(π+π/12)=-cos(π/12)=-(√6+√2)/4
cos(a+π/2)=cosacos(π/2)-sinasin(π/2)=cosa*0-sina*1=-sina
cos(-a+π/2)=cos(-a)cos(π/2)-sin(-a)sin(π/2)=cosa*0+sina*1=sina

cos7π/12=负2分之根3
cos(-61π/12)=2分之根3