使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?

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使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?
使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?

使(ax²-2x+y²)-(-x²+bxy+2y²)=5x²-9xy+cy²成立的a,b,c的值依次是?
(ax²-2xy+y²)-(-x²+bxy+2y²)
=ax²-2xy+y²+x²-bxy-2y²
=(a+1)x²-(2+b)xy-y²
=5x²-9xy+cy²
所以a+1=5
-(2+b)=-9
-1=c
所以
a=4,b=7,c=-1

a=4,b=7,c=-1

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