x²+4x=2 5x²-4x-12=0 4x²+4x+10=1-8xx²-6x+1=0 2x²-x=6 4x²-3x-1=x-2

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 07:45:38

x²+4x=2 5x²-4x-12=0 4x²+4x+10=1-8xx²-6x+1=0 2x²-x=6 4x²-3x-1=x-2
x²+4x=2 5x²-4x-12=0 4x²+4x+10=1-8x
x²-6x+1=0 2x²-x=6 4x²-3x-1=x-2

x²+4x=2 5x²-4x-12=0 4x²+4x+10=1-8xx²-6x+1=0 2x²-x=6 4x²-3x-1=x-2
x^2+4x=2
(x+2)^2=6
x+2=√6或x+2=-√6
x=√6-2或x=-√6 -2
5x^2-4x-12=0
(5x+6)(x-2)=0
x=-6/5或x=2
4x^2+4x+10=1-8x
4x^2+12x+9=0
(2x+3)^2=0
2x+3=0
x=-3/2
x^2-6x+1=0
(x-3)^2=8
x-3=2√2或x-3=-2√2
x=3+2√2或x=3-2√2
2x^2-x=6
2x^2-x-6=0
(2x+3)(x-2)=0
x=-3/2或x=2
4x^2-3x-1=x-2
4x^2-4x+1=0
(2x-1)^2=0
2x-1=0
x=1/2

1.x=正负根号6-2 2.x=2或-5分之6 3.x=正负2分之3倍根号2-2分之3
4.x=正负2倍根号2+3 5.x=2或-2分之3 6.x=2分之1

怎么算啊这个:X²+4X+Y²-2Y+5=0 则X²+Y²=?²²²²²²²²²²²²X²+4X+Y²-2Y+5X=0 则X²+Y²=? xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² 已知x² -XY = 2,Y² -XY= 5,求x² - 4x Y+ Y² = 2x² + xY -3Y² = x² + xY- 2Y² =求x² - 4x Y+ Y² = 1.(3x²+10x²+13x-27)/(x²+2x-3)2.(2x²+x³-2)/(x²-1)3.已知A=(3x)²-21x³-2x²+11x-2 B=3x³-5x²-4x+1求a²/b² 已知x²+4x+y²-2y+5=0,则x²+y²= 望有能者居之.分解因式.1、ab(c²-d²)+cd(a²-b²)2、(X²-4根号2X+4)3、(X²-2X)²-7(X²-2X)+124、X²-13X²+36[^3代表三的平方,^4代表四的平方,如此类推,5、已知a²+b²=-ab, 化简再求值[(x²+y²)²-4x²y²]÷(x²-y²)其实,x=2,y=2/3. 1.(x+y)²-4xy=( )²2.x²-( )+25y²=( )²3.x²-8x²y²+16y四次方=( )²4.7.2²-2.8²= . 4m²(2x-3y)²-m²(3x-2y)²=? 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 问几道有关分式的数学题 ,(1)[(5xy)/(x²+xy)]*[(xy+y²)/(2x²y²)]^3(2)[(x^3-3x+4)/(x²+2x-3)]÷[(x²-16)/(x²+6x+9)](3)(x²+x-3)/(x²+x-2)+1=(2x²+4x+1)/(x²+2x+1)(4)已知a²+4a+1=0 ,且(a^4+ xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 100²-99²+98²-97²+.4²-3²+2²-1²=(a+b)(a-b)-2(a²-5b²)=(x+2)(x+4)+x²-4=x²-y²+2x-2y= 4x²-3x=52 5x²=4-2x (-x+2x²+5)+(-3+4x²-6x)=? 两个初升高衔接教材的数学题.①(x²+x+1)(x²+x+2)-12=(x²+x+1)(x²+x+1+1)-12=(x²+x+1)²+(x²+x+1)-12=(x²+x-3)(x²+x+5)[十字相乘法]②(x²+x)²-8(x²+x)+12=(x²+x-2)(x²+x-6)[ (3x-2)²=4(x-3)² 在线求助完全平方公式因式分解(1)-a²-1+2a(2)2x²y-x²-xy²(3)4x²-20x+25(4)(x²+1)²-4x²(5)(2x-y)²-2(2x-y)+1(6)(x+y)²-2(x²-y²)+(x-y)²