1+3+5+7+``````+(2n-1)+(2n+1)+(2n+3)和103+105+107+······+2003+2005快,我急用

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1+3+5+7+``````+(2n-1)+(2n+1)+(2n+3)和103+105+107+······+2003+2005快,我急用
1+3+5+7+``````+(2n-1)+(2n+1)+(2n+3)和103+105+107+······+2003+2005
快,我急用

1+3+5+7+``````+(2n-1)+(2n+1)+(2n+3)和103+105+107+······+2003+2005快,我急用
1+3+5+7+``````+(2n-1)+(2n+1)+(2n+3)=(1+2n+3)(n+2)/2
=(n+2)^2
103+105+107+······+2003+2005
=(103+2005)*((2005-103)/2+1)

(n+1)的平方 1003408 求和公式首项与末项和乘项数除以二 项数等于末项与首项差除以公差加一