已知sin(π+α)=-1/2,计算(1)sin(π/2+α)(2)cos(α-3π/2)(3)tan(π/2-α)

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已知sin(π+α)=-1/2,计算(1)sin(π/2+α)(2)cos(α-3π/2)(3)tan(π/2-α)
已知sin(π+α)=-1/2,计算(1)sin(π/2+α)(2)cos(α-3π/2)(3)tan(π/2-α)

已知sin(π+α)=-1/2,计算(1)sin(π/2+α)(2)cos(α-3π/2)(3)tan(π/2-α)
sin(π+α)=-1/2,sin(π/2+α)=sin(π+α-π/2)=-cos(π+α)=±√3/2;
cos(α-3π/2)=cos(α-3π/2+2π)=cos(α+π/2)
=cos(α+π-π/2)=sin(π+α)=-1/2
tan(π/2-α)=-tan(α-π/2)=-tan(α+π-π/2)=-ctan(α+π)
=-cos(π+α)/sin(π+α)=±(√3/2)/(-1/2)=±√3