{int a,b; for(a=1,b=1;a=20) break; if(b%3==1) {b+=3; continue; } b-=5; } {int a,b;首先a=1,b=1,然后连续执行b+=3,a++为什么是这么做?在开始b=1的时候,b%3==1这个条件就不成立,为什么还要执行b+=3?谢啦,大师们!

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{int a,b; for(a=1,b=1;a=20) break; if(b%3==1) {b+=3; continue; } b-=5; } {int a,b;首先a=1,b=1,然后连续执行b+=3,a++为什么是这么做?在开始b=1的时候,b%3==1这个条件就不成立,为什么还要执行b+=3?谢啦,大师们!
{int a,b; for(a=1,b=1;a=20) break; if(b%3==1) {b+=3; continue; } b-=5; } {int a,b;
首先a=1,b=1,
然后连续执行b+=3,a++
为什么是这么做?在开始b=1的时候,b%3==1这个条件就不成立,为什么还要执行b+=3?
谢啦,大师们!

{int a,b; for(a=1,b=1;a=20) break; if(b%3==1) {b+=3; continue; } b-=5; } {int a,b;首先a=1,b=1,然后连续执行b+=3,a++为什么是这么做?在开始b=1的时候,b%3==1这个条件就不成立,为什么还要执行b+=3?谢啦,大师们!
b%3 的意思是求模,就是b除以3后的余数.
1%3 结果 1
4%3 结果 1
.
所以 b=1 时, b%3==1 成立.

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