∫ [(1-x-x^2)/(x^2+x^3) ]dx=?

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∫ [(1-x-x^2)/(x^2+x^3) ]dx=?
∫ [(1-x-x^2)/(x^2+x^3) ]dx=?

∫ [(1-x-x^2)/(x^2+x^3) ]dx=?
(1-x-x^2)/(x^2+x^3)
=(1+x-2x-x^2)/(x^2+x^3)
=1/x^2-2/x(x+1)-1/(x+1)
=1/x^2 - 2*(1/x - 1/(x+1))-1/(x+1)
=1/x^2 - 2/x + 1/(x+1)
然后代公式就行了
∫[1/x^2 - 2/x + 1/(x+1)]dx
=-1/x-2lnx+ln(x+1)+C

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