f(x)=1/[(x+1)In(x+1)]的导函数是什么?

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f(x)=1/[(x+1)In(x+1)]的导函数是什么?
f(x)=1/[(x+1)In(x+1)]的导函数是什么?

f(x)=1/[(x+1)In(x+1)]的导函数是什么?
f'(x)={[1/(x+1)][1/ln(x+1)]}'
=[1/(x+1)]'[1/ln(x+1)]+[1/(x+1)][1/ln(x+1)]'
=-1/[(x+1)²ln(x+1)]+[1/(x+1)][-1/ln²(x+1)][1/(x+1)]
=-1/[(x+1)²ln(x+1)]-1/[(x+1)²ln²(x+1)]
=-[ln(x+1)+1]/[(x+1)²ln²(x+1)]

f'(x)=-[1+ln(x+1))]/[(x+1)In(x+1)]^2

f(x)'=[1+ln(x+1)]/[(x+1)ln(x+1)]^2

f'=-[ln(x+1)+1]/[(x+1)In(x+1)]^2