第5题.

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第5题.

第5题.

第5题.
原式=sin(π/11)*cos(π/11)*cos(2π/11)*11)*cos(3π/11)*cos(4π/11)*cos(5π/11)
/ sin(π/11)
=1/2sin(2π/11)*cos(2π/11)*11)*cos(3π/11)*cos(4π/11)*cos(5π/11)
/ sin(π/11)
=1/2*1/2sin(4π/11)*cos(4π/11)*cos(3π/11)*cos(5π/11)
/ sin(π/11)
=1/8sin(8π/11))*cos(3π/11)*cos(5π/11)
/ sin(π/11)
=1/16sin(3π/11)*cos(3π/11)*cos(5π/11) [sin(8π/11))=sin(3π/11)]
/ sin(π/11)
=1/32sin(6π/11))*cos(5π/11)
/ sin(π/11)
=1/64sin(10π/11)/sin(π/11) [sin(6π/11))=sin(5π/11)]
=1/64 [sin(10π/11)=sin(π/11) ]

成个Sin派/11~

可以提取的。这种题经常见的。
原式
=(cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11*2sinπ/11)/2sinπ/11
=(sin2π/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11)/2sinπ/11
=(1/2*sin4π/11*cos3π/11*cos4π/11*cos5π/11)/2...

全部展开

可以提取的。这种题经常见的。
原式
=(cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11*2sinπ/11)/2sinπ/11
=(sin2π/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11)/2sinπ/11
=(1/2*sin4π/11*cos3π/11*cos4π/11*cos5π/11)/2sinπ/11
=(1/4*sin8π/11*cos3π/11*cos5π/11)/2sinπ/11
=(1/4*sin3π/11*cos3π/11*cos5π/11)/2sinπ/11
=(1/8*sin6π/11*cos5π/11)/2sinπ/11
=(1/8*sin5π/11*cos5π/11)/2sinπ/11
=(1/16*sin10π/11)/2sinπ/11
=1/32

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