计算:(1)(1/3√18-1/2√12)-(3√1/3-2√1/2) (2)1/√2+1/√3-√3/2-√2

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/02 21:38:34

计算:(1)(1/3√18-1/2√12)-(3√1/3-2√1/2) (2)1/√2+1/√3-√3/2-√2
计算:(1)(1/3√18-1/2√12)-(3√1/3-2√1/2) (2)1/√2+1/√3-√3/2-√2

计算:(1)(1/3√18-1/2√12)-(3√1/3-2√1/2) (2)1/√2+1/√3-√3/2-√2
(1)(1/3√18-1/2√12)-(3√1/3-2√1/2)
=√2-√3-√3+√2
=-2√3+2√2
(2)1/√2+1/√3-√3/2-√2
=√2/2+√3/3-√3/2-√2
= -√2/2-√3/6

(1/3√18-1/2√12)-(3√1/3-2√1/2)
=(√2-√3)-(√3-√2)
=√2-√3-√3+√2
=2√2-2√3

1/√2+1/√3-√3/2-√2
=1/2√2+1/3√3-1/2√3-√2
=1/2√2-√2+1/3√3-1/2√3
=-1/2√2-1/6√3