1、2、3、4、······2008这2008个数的最小公倍数等与多少个2与一个基数的积

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1、2、3、4、······2008这2008个数的最小公倍数等与多少个2与一个基数的积
1、2、3、4、······2008这2008个数的最小公倍数等与多少个2与一个基数的积

1、2、3、4、······2008这2008个数的最小公倍数等与多少个2与一个基数的积
把1-2008都累乘起来,肯定是这2008个数的公倍数.但最小公倍数要除以一些共同的因子.比如4中包含了2,9中包含了3,都要一一排除.这样就不难回答以上的问题.只要找出一个含2最多的数就是这个最小公倍数中2的最多次幂了.应该是2的10次,1024.故而答案为10.

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