1.y=(1-2x^2)/(1+2x^2)2.y=2x-根号下（x-1)

来源：学生作业帮助网编辑：作业帮时间：2024/04/24 05:21:12

1.y=(1-2x^2)/(1+2x^2)2.y=2x-根号下（x-1)
1.y=(1-2x^2)/(1+2x^2)
2.y=2x-根号下（x-1)

1.y=(1-2x^2)/(1+2x^2)2.y=2x-根号下（x-1)
1.y=(1-2x^2)/(1+2x^2)
=(-(1+2x^2)+2)/(1+2x^2)
=-1+2/(1+2x^2)
2/(1+2x^2)的值域为(0,2〕,
所以原函数的值域为(-1,1〕;
2.设t=根号下（x-1) ,则x=t平方+1,且t>=0;
原式等价于
y=2*(t^2+1)-t
=2*t^2-t+2
=2*(t-1/4)^2+15/8
2*(t-1/4)^2的值域为〔0,+∞),
所以函数值域为〔15/8,+∞).

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