求证:1/cosα-tanα=1/tan(π/4+α/2)

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求证:1/cosα-tanα=1/tan(π/4+α/2)
求证:1/cosα-tanα=1/tan(π/4+α/2)

求证:1/cosα-tanα=1/tan(π/4+α/2)
1/cosα-tanα=1/cosα-sinα/cosα=(1-sinα)/cosα
1/tan(π/4+α/2)=1/(sin(π/4+α/2)/cos(π/4+α/2))=cos(π/4+α/2)/sin(π/4+α/2)=2cos(π/4+α/2)^2/(2sin(π/4+α/2)cos(π/4+α/2))=(1+cos(π/2+α))/sin(π/2+α/2)=(1-sinα)/cosα