(2+1)(2²+1­­)(2^4+1)...(2^n+1)

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(2+1)(2²+1­­)(2^4+1)...(2^n+1)
(2+1)(2²+1­­)(2^4+1)...(2^n+1)

(2+1)(2²+1­­)(2^4+1)...(2^n+1)
原式=(2-1)(2+1)(2²+1­­)(2^4+1)...(2^n+1)
=(2²-1)(2²+1­­)(2^4+1)...(2^n+1)
=2^2n-1

给算式前面乘以(2-1) 2-1=1 后面不用再除..
或者把(2+1)变成(2²-1) 2+1=2²-1
最后变成(2^n-1)(2^n+1)
平方差- =...你懂得...