用分解因式法解方程.(x+1)²-2(x+1)(2-x)+(x-2)²=0

用分解因式法解方程.(x+1)²-2(x+1)(2-x)+(x-2)²=0
用分解因式法解方程.(x+1)²-2(x+1)(2-x)+(x-2)²=0

用分解因式法解方程.(x+1)²-2(x+1)(2-x)+(x-2)²=0
(x+1)²-2(x+1)(2-x)+(x-2)²=0
(x+1)²+2(x+1)(x-2)+(x-2)²=0
(x+1 +x-2) ² = 0
2x-1 = 0
x= 2分之1
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(x+1)²-2(x+1)(2-x)+(x-2)²=0
(x+1)²-(x+1)(2-x)-(x+1)(2-x)+(x-2)²=0
(x+1)(x+1-2+x)+(x+1)(x-2)+(x-2)²=0
(x+1)(2x-1)+(x-2)(x+1+x-2)=0
(x+1)(2x-1)+(x-2)(2x-1)=0
(2x-1)(x+1+x-2)=0
(2x-1)(2x-1)=0
(2x-1)²=0
x=1/2