3^3*9^m+4/27^(2m-1)的值为729,试求m的值这是数学资料上的题，刚刚在网上搜，我也觉得有问题！

m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m求m的值 已知9^m*27^m-1除以3^2m=27,m的值 如果9^m+3*27^m/3^2m-1=81,求m的值 计算(3m^2)^3-7m^3【m^3-m(4m^2+1)】等于 A.7m^3+9m^4 B.7m^4+48m^6 C.-7m^2+7m^4+31m^5 D.-7m^3-28m计算(3m^2)^3-7m^3【m^3-m(4m^2+1)】等于 A.7m^3+9m^4 B.7m^4+48m^6 C.-7m^2+7m^4+31m^5 D.-7m^3-28m^5-7m^6+27m^7 正确率一定要高! 已知m＞4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3| 已知m+1/m=3,计算(m^4+m^2+1)/m^2的值 若m为正整数,且m不能被4整除,试说明1^m+2^m+3^m+4^m+…+9^m一定是5的倍数 计算：m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m m-2m-3m+4m-5m-6m+7m-8m-9m+.+2002m-2003m-2004m 当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m²]-3m} (m+3m+5m+.+2008m)-(2m+4m+6m+.+2009m)今天刚考完试,想确认一下,,我写的是2009(m+3m+5m+.+2009m)-(2m+4m+6m+.+2008m) 若m×(m+1)(m+2)(m+3)(m+4)共有40个不同的约数,则m= 计算：1/m(m+1)+1/(m+1)(m+2)+1/(m+2)(m+3)+1/(m+3)(m+4)+1/(m+4)(m+5)+.+1/(m+9)(m+10) 1/m(m+1)+1/(m+1)(m+2)+1/(m+2)(m+3)+.+1/(m+9)(m+10) 式子m(m=1)(m+2)(m+3)(m+4)(m+5)(m+6)...(m+20)/20!可表示为组合问题解的详细点啊 (M-1/M^2+6M+9)+(M-3/M^2+4M+3)怎么化简 同底数幂的乘法的计算题,3×9×27×3^mm^3×m^5+m^2×m^6-2m×m^3×m^4 (3m的立方-4m平方+m)/m-m