解不等式:0≤x^2+4x+3≤8

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/07 06:21:07

解不等式:0≤x^2+4x+3≤8
解不等式:0≤x^2+4x+3≤8

解不等式:0≤x^2+4x+3≤8
先求0≤x^2+4x+3
0≤(x+1)(x+3)得:x≥-1或x≤-3
再求x^2+4x+3≤8
x^2+4x-5≤0
(x+5)(x-1)≤0得:-5≤x≤1
两者联立可得:-5≤x≤-3或-1≤x≤1

(-5,-1]

0<=(x+1)(x+3)
x<=-3, x>=-1
x^2+4x-5<=0
(x+5)(x-1)<=0
-5<=x<=1
-5<=x<=-3
-1<=x<=1