1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做

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1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做
1.a1=1,an+1=an+2n-1,求an
2.a1=1,an+1=2an+2n-1,求an
3.a1=1,an+1=3an+3n,求an
4.a1=1,an+1=3an+6,求an
就这4个,用累加或累乘的方法做

1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做
a2-a1=1
a3-a2=3
a4-a3=5
.
an-an_1=2n-3
所以
an-a1=1+3+5+.+2n-3
=n-1+(n-1)(n-2)
=(n-1)平方
所以an=n^2-2n (n>1)

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