求5x*x+5y*y+8xy-2y-2x+2=0的实数解

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求5x*x+5y*y+8xy-2y-2x+2=0的实数解
求5x*x+5y*y+8xy-2y-2x+2=0的实数解

求5x*x+5y*y+8xy-2y-2x+2=0的实数解
解:
5x^2+5y^2+8xy+2y-2x+2=0
即:4(x+y)^2+(x-1)^2+(y+1)^2=0
即:x+y=0,
且:x=1,y=-1
解为:x=1,y=-1.

解:
5x^2+5y^2+8xy+2y-2x+2=0
即:4(x+y)^2+(x-1)^2+(y+1)^2=0
即:x+y=0,
且:x=1,y=-1
解为:x=1,y=-1.

5x^2+5y^2+8xy+2y-2x+2=0
4(x+y)^2+(x-1)^2+(y+1)^2=0
x+y=0,
x=1,y=-1