【(x^2-4分之x^2-x-6)+(x+2分之x-3)】除以(x+1分之x-3),帮帮忙明天就要交,

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 13:52:12

【(x^2-4分之x^2-x-6)+(x+2分之x-3)】除以(x+1分之x-3),帮帮忙明天就要交,
【(x^2-4分之x^2-x-6)+(x+2分之x-3)】除以(x+1分之x-3),帮帮忙明天就要交,

【(x^2-4分之x^2-x-6)+(x+2分之x-3)】除以(x+1分之x-3),帮帮忙明天就要交,
[(x^2-x-6)/(x^2-4)+(x-3)/(x+2)]÷(x-3)/(x+1)
=[(x-3)(x+2)/(x-2)(x+2)+(x-3)/(x+2)]÷(x-3)/(x+1)
=[(x-3)/(x-2)+(x-3)/(x+2)]÷(x-3)/(x+1)
=[(x-3)/(x-2)+(x-3)/(x+2)]*(x+1)/(x-3)
=(x-3)/(x-2)*(x+1)/(x-3)+(x-3)/(x+2)*(x+1)/(x-3)
=(x+1)/(x-2)+(x+1)/(x+2)
=(x+1)(x+2)/[(x-2)(x+2)]+(x+1)(x-2)/[(x-2)(x+2)]
=(x+1)[(x+2)+(x-2)]/[(x-2)(x+2)]
=2x(x+1)/[(x-2)(x+2)]

【(x^2-4分之x^2-x-6)+(x+2分之x-3)】除以(x+1分之x-3)
=[(x²-x-6)/(x²-4)+(x-3)/(x+2)]÷(x-3)/(x+1)
=[(x-3)(x+2)/(x-2)(x+2)+(x-3)/(x+2)]÷(x-3)/(x+1)
=(x-3)[1/(x-2)+1/(x+2)]÷(x-3)/(x+1)
=(x+2+x-2)/(x-2)(x+2)(x+1)
=2x/[(x-2)(x+1)(x+2)

(x-2分之x减x+2分之x)乘4x分之2-x (x-2分之x-x+2分之x)÷x平方-4分之4x x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8 (解方程) x^2+x-6分之x^2+3x-x^2-4分之x+2计算 1.计算①(x-1-x+1分之8)×x+3分之x+1;②x+3y分之x-y÷x²+6xy+9y²分之x²-y²-x+y分之2y;③(x-x+1分之2x)÷x²-1分之x²-2x+1④(x²-2x分之x+2-x²-4x+4分之x-1)÷x³-2x²分之x-4 通分一,x平方-x+3分之6x+1与-x平方+x-3分之4x-3 二(x-1)(x-2)分之3x与(x-1)(2-x)分之3+x 通分一,x平方-x+3分之6x+1与-x平方+x-3分之4x-3 二(x-1)(x-2)分之3x与(x-1)(2-x)分之3+x 通分一,x平方-x+3分之6x+1与-x平方+x-3分之4x-3 二(x-1)(x-2)分之 3x与 (x-1)(2-x)分之3+x (x+1分之x+6)-(x^+3x+2分之3x^+10x+4)+(x+2分之2x+1)=0,解这个方程 x+2分之x=x-1分之x x平方+x分之4=x+1分之6-x分之1 x-3分之2x-1=1-3-x分之5x+2分之x=x-1分之x x平方+x分之4=x+1分之6-x分之1 x-3分之2x-1=1-3-x分之5 (x+2分之3x-x+2分之x)/x平方-4分之x(x-1)=4 (x-2分之3x-x+2分之1)乘x分之x平方-4 (x^2-x-6分之x^2-4+x-3分之x+2)除以x-3分之x+1 (x+2分之3x-x+2分之x)/x平方-4分之x(x-1)=4 1.【x-1分之x平方+3x+2】+【6分之2+x-x平方】-【10-x分之4-x平方】2.【x+1-1分之1-x】除以【x-x平方分之x-1】3.【x平方-4分之x平方-x-6】+【x+2分之x-3】这个结果再除以【x+1分之x-3】4.【x分之x-y】乘以 (X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0 4分之x-6-x=2分之x+5 解方程:x-19分之5x-96+x-9分之x-8=x-6分之4x-19+x-8分之2x-21解方程:(x-19)分之(5x-96)+(x-9)分之(x-8)=(x-6)分之(4x-19)+(x-8)分之(2x-21) (x-2分之x-1)/2-x分之4x