已知增函数y=f(x)定义域是(o,+无穷),且满足f(2)=1,f(xy)=f(x)+f(y),求满足f(x)+f(x-3)=

已知增函数y=f(x)定义域是(o,+无穷),且满足f(2)=1,f(xy)=f(x)+f(y),求满足f(x)+f(x-3)=
已知增函数y=f(x)定义域是(o,+无穷),且满足f(2)=1,f(xy)=f(x)+f(y),求满足f(x)+f(x-3)=

已知增函数y=f(x)定义域是(o,+无穷),且满足f(2)=1,f(xy)=f(x)+f(y),求满足f(x)+f(x-3)=
由f(x)+f(x-3)=0,x-3>0 即x>3
(2)f(x)+f(x-3)=f[x(x-3)]=