计算1/i+1/(1+i)+1/(1-i)+1/(1-根3)
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计算1/i+1/(1+i)+1/(1-i)+1/(1-根3)
计算1/i+1/(1+i)+1/(1-i)+1/(1-根3)
计算1/i+1/(1+i)+1/(1-i)+1/(1-根3)
1/i+1/(1+i)+1/(1-i)+1/(1-根3【i】)
=-i+(1-i)/2+(1+i)/2+(1+√3i)/4
=-i+1+1/4+√3i/4
=5/4+(√3-4)i/4
1/i+1/(1+i)+1/(1-i)+1/(1-根3)
=-i+(1-i)/2+(1+i)/2+-(√3+1)/2
=-i+1-1/2-√3/2
=(1-√3)/2-i
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