[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2=0[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2-24=0 问题有错漏…补上
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[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2=0[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2-24=0 问题有错漏…补上
[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2=0
[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2-24=0 问题有错漏…补上
[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2=0[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2-24=0 问题有错漏…补上
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[2+2k(5k-3)]^2-4(1+k^2)(5k-3)^2-24=0
[1+k(5k-3)]^2-(1+k^2)(5k-3)^2-6=0
1+2k(5k-3)+k^2(5k-3)^2-(1+k^2)(5k-3)^2-6=0
2k(5k-3)+(k^2-1-k^2)(5k-3)^2-5=0
(5k-3)^2-2k(5k-3)+5=0
15k^2-24k+14=0
b^2-4ac小于零 此题无解
(4k^2+7k)+(-k^2+3k-1)
k(k+2)(2k+5)+3 如何变成 (k+1)(k+3)(2k+1)
当k等于?时,3k(2k-5)+2k(1-3k)=52
2k/(3k-1)=4k/(3k+2)求k
[k*(2-4k)/(1+2k)]+2k+1
3×k×k-2k-1=-1.k等于
请问1^k+2^k+3^k+.+n^k=?
(k*k*k-2k+4)/4k
4k^2-4(k+1)(k-3)
数式变形(1) K^3-2K+4/K
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求证:lim1^k+2^k+3^k+4^k+.n^k/n^(k+1)=1/k+1n是正整数,后面的k+1有括号的
求和:1/k(k+1)(k+2)
化简:k-1/k²-4k+4÷1-k/k²-4的结果是( ) A、2-k/k+2 B、k+2/k-2 C、k+2/2-k D、k-2/k+2
证明:1/(3k+2)+1/(3k+3)+1/(3k+4)>1/(k+1)
数学方程求解1-2k+k^2-2k^3-k^4=0
(3k^2+7k)+(4k^2-3k+1)
k-4-2k|/√(k^2+1)= 3 K=?