2x^2-xy-y^2-4x-5y-6
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2x^2-xy-y^2-4x-5y-6
2x^2-xy-y^2-4x-5y-6
2x^2-xy-y^2-4x-5y-6
因式分解吗?
用双十字相乘
1 -1 -3
2 1 2
所以原式=(x-y-3)(2x+y+2)
因式分解 x-xy+3y-3x 2x+xy-y-4x+5y-6
2X^+XY-Y^-4X+5Y-6
2x^+xy-y^-4x+5y-6=?
5x^3y*(-3y)^2+(-6xy)^2*(-xy)+xy^3*(-4x^2)
诺x+y=6,xy=4 求(5x-4y-3xy)-(8x-y+2xy)
因式分解 (3x+2y)-(x-y)² x²-xy+3y-3x 2x²+xy-y²-4x+5y-6
化简:3x^2-[5xy-(x^y-3xy)+4x^2y-8xy]
因式分解 求过程 x-xy+3y-3x 2x+xy-y-4x+5y-6
3x平方-5x平方y-{2x平方y+6xy平方-[2xy平方-3x平方y+(3x平方y-4xy平方】}
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6
3(x-y)²-7(x-y)+8(x-y)²+6(x-y)求详细过程(2) 5xy-4x²y-8xy²+3xy-xy²+4x²y
2x^2-3xy+6y^2-x^2+4xy-5y^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
已知2/x-1/y=3,则(2y-x+4xy)/(3x-6y-5xy)=?
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)²
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2