y=sinx+sin(x-π/2 )的最大值是多少啊?
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y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )=sinx-cosx=√2*sin(x-π/4)
y最大值=√2
y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )的最大值是多少啊?
y=sinx+sin(x-π/2 )=sinx-cosx=√2*sin(x-π/4)
y最大值=√2