(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急)
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(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急)
(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=
化简(急)
(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急)
1-cos^4x-sin^4x
=1-(cos^4x+sin^4x)
=1-[(cos^2x+sin^2x)^2-2cos^2xsin^2x]
=1-(1-2cos^2xsin^2x)
=2cos^2xsin^2x
1-cos^6x-sin^6x
=1-(cos^2x+sin^2x)(cos^4x-cos^2xsin^2x+sin^4x)
=1-[(cos^2x+sin^2x)^2-3cos^2xsin^2x]
=1-[1-3cos^2xsin^2x]
=3cos^2xsin^2x
原式=2cos^2xsin^2x/3cos^2xsin^2x=2/3
用计算器算卅。。。
(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=
=[(sin²x+cos²x)²-cos^4X-sin^4x)]/[1-(cos²x+sin²x)(cos²x-sin²xcos²x+sin²x)]
=2sin²xcos²x/[1-(1-sin²xcos²x)]
=2sin²xcos²x/sin²xcos²x
=2
化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x
化简(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x)
求值:(1-sin^6 x-cos^6 x)/(1-sin^4 x-cos^4 x)
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
(1-cos^4X-sin^4x)∕(1-cos^6x-sin^6x)=化简(急)
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